electronvolts to foot-pounds
Convert electronvolt to foot-pound — instant, free, with the formula shown.
How to convert electronvolt to foot-pound
To convert electronvolt to foot-pound, multiply by 1.1817e-19:
For example, 10 eV × 1.1817e-19 = 1.1817e-18 ft·lb.
eV to ft·lb conversion table
| electronvolts (eV) | foot-pounds (ft·lb) |
|---|---|
| 1 eV | 1.1817e-19 ft·lb |
| 2 eV | 2.3634e-19 ft·lb |
| 5 eV | 5.9085e-19 ft·lb |
| 10 eV | 1.1817e-18 ft·lb |
| 25 eV | 2.9543e-18 ft·lb |
| 50 eV | 5.9085e-18 ft·lb |
| 100 eV | 1.1817e-17 ft·lb |
| 250 eV | 2.9543e-17 ft·lb |
| 500 eV | 5.9085e-17 ft·lb |
| 1000 eV | 1.1817e-16 ft·lb |
Other electronvolt conversions
Convert to foot-pound from another unit
eV to ft·lb — frequently asked
How many foot-pounds are in 1 electronvolt?
1 electronvolt = 1.1817e-19 foot-pounds (eV × 1.1817e-19 = ft·lb).
What is the formula to convert electronvolt to foot-pound?
Multiply your electronvolt value by 1.1817e-19 to get foot-pound.
How do I convert 10 electronvolts to foot-pounds?
10 eV = 1.1817e-18 ft·lb. For 100 eV the answer is 1.1817e-17 ft·lb. Use the calculator on this page for any other value.
When to convert electronvolt to foot-pound
Energy conversion — common questions
Is a food calorie the same as a calorie?
No — a food 'Calorie' (capital C) actually means 1 kilocalorie = 1,000 small calories = 4,184 J. Nutrition labels typically write 'cal' meaning kcal.
How many joules in 1 kWh?
1 kWh = 3,600,000 J (3.6 MJ). Because 1 kW × 1 hour = 1,000 W × 3,600 s = 3,600,000 J.
What is a BTU?
British Thermal Unit — the energy required to raise 1 pound of water by 1 °F. 1 BTU ≈ 1,055 J.