foot-pounds to electronvolts
Convert foot-pound to electronvolt — instant, free, with the formula shown.
How to convert foot-pound to electronvolt
To convert foot-pound to electronvolt, multiply by 8.4624e+18:
For example, 10 ft·lb × 8.4624e+18 = 8.4624e+19 eV.
ft·lb to eV conversion table
| foot-pounds (ft·lb) | electronvolts (eV) |
|---|---|
| 1 ft·lb | 8.4624e+18 eV |
| 2 ft·lb | 1.6925e+19 eV |
| 5 ft·lb | 4.2312e+19 eV |
| 10 ft·lb | 8.4624e+19 eV |
| 25 ft·lb | 2.1156e+20 eV |
| 50 ft·lb | 4.2312e+20 eV |
| 100 ft·lb | 8.4624e+20 eV |
| 250 ft·lb | 2.1156e+21 eV |
| 500 ft·lb | 4.2312e+21 eV |
| 1000 ft·lb | 8.4624e+21 eV |
Other foot-pound conversions
Convert to electronvolt from another unit
ft·lb to eV — frequently asked
How many electronvolts are in 1 foot-pound?
1 foot-pound = 8.4624e+18 electronvolts (ft·lb × 8.4624e+18 = eV).
What is the formula to convert foot-pound to electronvolt?
Multiply your foot-pound value by 8.4624e+18 to get electronvolt.
How do I convert 10 foot-pounds to electronvolts?
10 ft·lb = 8.4624e+19 eV. For 100 ft·lb the answer is 8.4624e+20 eV. Use the calculator on this page for any other value.
When to convert foot-pound to electronvolt
Energy conversion — common questions
Is a food calorie the same as a calorie?
No — a food 'Calorie' (capital C) actually means 1 kilocalorie = 1,000 small calories = 4,184 J. Nutrition labels typically write 'cal' meaning kcal.
How many joules in 1 kWh?
1 kWh = 3,600,000 J (3.6 MJ). Because 1 kW × 1 hour = 1,000 W × 3,600 s = 3,600,000 J.
What is a BTU?
British Thermal Unit — the energy required to raise 1 pound of water by 1 °F. 1 BTU ≈ 1,055 J.